type 6 fractions based ratio & proportion problems Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 1 [SSC CGL Tier-I 2016]
Rs. 782 is divided into three parts in the ratio $1/2 : 2/3 : 3/4$, the first part is
a) Rs. 190
b) Rs. 196
c) Rs. 204
d) Rs. 182
Answer »Answer: (c)
A : B : C = $1/2 : 2/3 : 3/4$
= $(1/2 ×12) : (2/3 × 12) : (3/4 × 12)$
= 6 : 8 : 9
Sum of the terms of ratio
= 6 + 8 + 9 = 23
First part
= Rs.$(6/23 × 782)$ = Rs.204
Question : 2 [SSC CHSL 2011]
If x : y = 3 : 4, then the value of (4x - y) : (2x + 3y) is
a) 4 : 3
b) 8 : 3
c) 8 : 9
d) 4 : 9
Answer »Answer: (d)
$x/y = 3/4$
${4x - y}/{2x +3y} ={4x/y-1}/{2x/y+3}$
= ${4 × 3/4 - 1}/{2× 3/4+ 3}$
= $2/{3/2+ 3} = {2× 2}/9 = 4 : 9$
Question : 3 [SSC CGL Tier-I 2016]
A and B together have Rs. 6300. If $5/19$ th of A’s amount is equal to $2/5$ th of B’s amount. The amount of ‘B’ is
a) Rs.2300
b) Rs.4000
c) Rs.3800
d) Rs.2500
Answer »Answer: (d)
According to the question,
${5A}/19 = {2B}/5$
$5A = {19 × 2B}/5$
A = ${38 × B}/{5× 5}$
A : B = 38 : 25
Sum of the terms of ratio
= 38 + 25 = 63
B’s share = Rs.$(25/63 × 6300)$
= Rs.2500
Question : 4 [SSC CGL Tier-I 2015]
If $x/y = 3/4$, the ratio of (2x + 3y) and (3y - 2x) is
a) 1 : 1
b) 3 : 1
c) 3 : 2
d) 2 : 1
Answer »Answer: (b)
$x/y = 3/4$ (Given)
${2x + 3y}/{3y - 2x} = {2x/y +{3y}/y}/{{3y}/y-{2x}/y}$
(Dividing numerator and denominator by y)
= ${2x/y+3}/{3 - 2 x/y} = {2× 3/4+3}/{3-2× 3/4}$
= ${3/2 + 3}/{3 - 3/2}$
= ${3 + 6}/{6 - 3}= 9/3$ = 3 : 1
Question : 5 [SSC CPO SI 2016]
Two numbers are in the ratio 1$1/2 : 2 2/3$, when each of these is increased by 15, they are in the ratio 1$2/3 : 2 1/2$ . The greater of the numbers
a) 48
b) 64
c) 36
d) 27
Answer »Answer: (a)
First number = ${3x}/2$
and second number = ${8x}/3$
According to the question,
${{3x}/2 + 15}/{{8x}/3 + 15}= {5/3}/{5/2}$
${{3x+ 30}/2}/{{8x + 45}/3} = 5/3 × 2/5 = 2/3$
${(3x + 30)× 3}/{(8x + 45) × 2} = 2/3$
32x + 180 = 27x + 270
32x - 27x = 270 - 180
5x = 90
$x = 90/5$ = 18
Larger number = ${8x}/3$
= ${8 × 18}/3$ = 48
IMPORTANT quantitative aptitude EXERCISES
-
199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
-
Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
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159+ Ratios Proportions Addition Subtraction product MCQ »
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199+ Ratio Proportion Income, Expenditure Problems MCQS »
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199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
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259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
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199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
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249+ Ratio and Proportion Coins Based Questions Answers »
type 6 fractions based ratio & proportion problems Online Quiz
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